What is (x-6)^2+(y-6)^2=9 ?

The solution to (x-6)^2+(y-6)^2=9 is Circle with (a,b)=(6,6),r=3

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(x-6)^2+(y-6)^2=9

(x - 6)^{2} + (y - 6)^{2} = 9

(a, b) = (6, 6), r = 3

Solution steps

(x - 6)^{2} + (y - 6)^{2} = 9

Rewrite

(x - 6)^{2} + (y - 6)^{2} = 9

in the form of the standard circle equation

(x - 6)^{2} + (y - 6)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (6, 6), r = 3

4 x^{2} + 4 y^{2} = 5

(x + 2)^{2} + (y + 1)^{2} = \frac{13}{2}

3 - y = x^{2} + y^{2}

3 x^{2} + 3 y^{2} + 12 x + 12 y = 4

2 x^{2} + 2 y^{2} - 12 x + 4 y - 12 = 0

What is (x-6)^2+(y-6)^2=9 ?
The solution to (x-6)^2+(y-6)^2=9 is Circle with (a,b)=(6,6),r=3