What is (x-5)^2+(Y(x)+2)^2=16 ?

The solution to (x-5)^2+(Y(x)+2)^2=16 is Circle with (a,b)=(5,-2),r=4

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(x-5)^2+(Y(x)+2)^2=16

(x - 5)^{2} + (Y (x) + 2)^{2} = 16

(a, b) = (5, - 2), r = 4

Solution steps

(x - 5)^{2} + (y + 2)^{2} = 16

Rewrite

(x - 5)^{2} + (y + 2)^{2} = 16

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (5, - 2), r = 4

x^{2} - 2 x + y^{2} + 4 y = 0

2 x^{2} + 12 x + 2 y^{2} - 2 y - 3 = 0

x^{2} + y^{2} + 6 x - 13 y + 13 = 0

x^{2} + y^{2} + 4 x + 8 y + 4 = 0

5 x^{2} + 5 y^{2} + 20 x + 30 y - 310 = 0

What is (x-5)^2+(Y(x)+2)^2=16 ?
The solution to (x-5)^2+(Y(x)+2)^2=16 is Circle with (a,b)=(5,-2),r=4