What is 5x^2+5y^2+20x+30y-310=0 ?

The solution to 5x^2+5y^2+20x+30y-310=0 is Circle with (a,b)=(-2,-3),r=5sqrt(3)

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5x^2+5y^2+20x+30y-310=0

5 x^{2} + 5 y^{2} + 20 x + 30 y - 310 = 0

(a, b) = (- 2, - 3), r = 53

Solution steps

5 x^{2} + 5 y^{2} + 20 x + 30 y - 310 = 0

Rewrite

5 x^{2} + 5 y^{2} + 20 x + 30 y - 310 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 3))^{2} = (53)^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 3), r = 53

x^{2} + y^{2} = \frac{- x - y + 2}{2}

(X + 7)^{2} + (y - 1)^{2} = 9

(x^{2} - 2) + (y^{2} + 4) = 4

(x - 3)^{2} + (y + 1)^{2} = 49

(x + 7)^{2} + (y - 6)^{2} = 361

What is 5x^2+5y^2+20x+30y-310=0 ?
The solution to 5x^2+5y^2+20x+30y-310=0 is Circle with (a,b)=(-2,-3),r=5sqrt(3)