What is 16=(x-9)^2+(y+4)^2 ?

The solution to 16=(x-9)^2+(y+4)^2 is Circle with (a,b)=(9,-4),r=4

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16=(x-9)^2+(y+4)^2

16 = (x - 9)^{2} + (y + 4)^{2}

(a, b) = (9, - 4), r = 4

Solution steps

16 = (x - 9)^{2} + (y + 4)^{2}

Rewrite

16 = (x - 9)^{2} + (y + 4)^{2}

in the form of the standard circle equation

(x - 9)^{2} + (y - (- 4))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (9, - 4), r = 4

1 = x^{2} + y^{2} - 1

(x + 16)^{2} + (y + 7)^{2} = 9

x^{2} + y^{2} + 6 x + 14 y + 49 = 0

\frac{( x + 2 ) ^{2}}{3} + \frac{z ^{2}}{3} = 3

x^{2} + y^{2} + 4 x - 6 y - 26 = 0

What is 16=(x-9)^2+(y+4)^2 ?
The solution to 16=(x-9)^2+(y+4)^2 is Circle with (a,b)=(9,-4),r=4