What is x^2+y^2+4x-6y-26=0 ?

The solution to x^2+y^2+4x-6y-26=0 is Circle with (a,b)=(-2,3),r=sqrt(39)

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x^2+y^2+4x-6y-26=0

x^{2} + y^{2} + 4 x - 6 y - 26 = 0

(a, b) = (- 2, 3), r = 39

Solution steps

x^{2} + y^{2} + 4 x - 6 y - 26 = 0

Rewrite

x^{2} + y^{2} + 4 x - 6 y - 26 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 3)^{2} = (39)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 3), r = 39

12 X^{2} + 12 Y^{2} = 144

2. 3^{2} = (x + 3)^{2} + (y - 1)^{2}

(x + 1)^{2} + (y + 3)^{2} = 4

2 x^{2} + 2 y^{2} = 11

x^{2} + y^{2} + 18 x + 2 y + 4 = 0

What is x^2+y^2+4x-6y-26=0 ?
The solution to x^2+y^2+4x-6y-26=0 is Circle with (a,b)=(-2,3),r=sqrt(39)