What is x^2+y^2+18x+2y+4=0 ?

The solution to x^2+y^2+18x+2y+4=0 is Circle with (a,b)=(-9,-1),r=sqrt(78)

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x^2+y^2+18x+2y+4=0

x^{2} + y^{2} + 18 x + 2 y + 4 = 0

(a, b) = (- 9, - 1), r = 78

Solution steps

x^{2} + y^{2} + 18 x + 2 y + 4 = 0

Rewrite

x^{2} + y^{2} + 18 x + 2 y + 4 = 0

in the form of the standard circle equation

(x - (- 9))^{2} + (y - (- 1))^{2} = (78)^{2}

Therefore the circle properties are:

(a, b) = (- 9, - 1), r = 78

x^{2} + y^{2} + 4 x - 3 y - 1 = 0

2 (a^{2} + b^{2}) = (1003)^{2} + (103)^{2}

y^{2} = - x^{2} - 4 x + 12

x^{2} + y^{2} - 20 x + 8 y + 116 = 200

(x - 4)^{2} + (y - 1)^{2} = 36

What is x^2+y^2+18x+2y+4=0 ?
The solution to x^2+y^2+18x+2y+4=0 is Circle with (a,b)=(-9,-1),r=sqrt(78)