What is x^2+y^2-18x+12y+81=0 ?

The solution to x^2+y^2-18x+12y+81=0 is Circle with (a,b)=(9,-6),r=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-18x+12y+81=0

x^{2} + y^{2} - 18 x + 12 y + 81 = 0

(a, b) = (9, - 6), r = 6

Solution steps

x^{2} + y^{2} - 18 x + 12 y + 81 = 0

Rewrite

x^{2} + y^{2} - 18 x + 12 y + 81 = 0

in the form of the standard circle equation

(x - 9)^{2} + (y - (- 6))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (9, - 6), r = 6

x^{2} + y^{2} - 78 y - 1843 = 0

x^{2} + y^{2} - 14 x + 14 y = 132

(x^{2} + 10 x + 25) + (y^{2} - 2 y + 1) = 9

x^{(2)} + (y + 1)^{(2)} = 1

(x - 2)^{2} + (y - 1)^{2} = 5

What is x^2+y^2-18x+12y+81=0 ?
The solution to x^2+y^2-18x+12y+81=0 is Circle with (a,b)=(9,-6),r=6