What is x^2+2x+1+y^2-3+(-9)/4 =0 ?

The solution to x^2+2x+1+y^2-3+(-9)/4 =0 is Circle with (a,b)=(-1,0),r=(sqrt(21))/2

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x^2+2x+1+y^2-3+(-9)/4 =0

x^{2} + 2 x + 1 + y^{2} - 3 + \frac{- 9}{4} = 0

(a, b) = (- 1, 0), r = \frac{21}{2}

Solution steps

x^{2} + 2 x + 1 + y^{2} - 3 + \frac{- 9}{4} = 0

Rewrite

x^{2} + 2 x + 1 + y^{2} - 3 + \frac{- 9}{4} = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 0)^{2} = (\frac{21}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 1, 0), r = \frac{21}{2}

x^{2} + y^{2} - 14 x - 18 y + 105 = 0

x^{(2)} + (y + 2)^{(2)} = 36

x^{2} + y^{2} + 2 x - 2 y - 1 = 4

x^{2} + y^{2} + 2 x - 2 y - 1 = 2

y^{2} = - (x + 2) (x - 3)

What is x^2+2x+1+y^2-3+(-9)/4 =0 ?
The solution to x^2+2x+1+y^2-3+(-9)/4 =0 is Circle with (a,b)=(-1,0),r=(sqrt(21))/2