What is 0+y^2+z^2=1 ?

The solution to 0+y^2+z^2=1 is Circle with (a,b)=(0,0),r=1

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0+y^2+z^2=1

0 + y^{2} + z^{2} = 1

(a, b) = (0, 0), r = 1

Solution steps

0 + y^{2} + z^{2} = 1

Rewrite

0 + y^{2} + z^{2} = 1

in the form of the standard circle equation

(y - 0)^{2} + (z - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 1

(x - 2)^{2} + (y - 17)^{2} = 64

(x + 5)^{2} + (y - 1)^{2} = 7

(x - (- 2))^{2} + (y - 1)^{2} = 5^{2}

(x - 3)^{2} + (y + 13)^{2} = 9

x^{2} + y^{2} - 4 x + 2 y - 2 = 0

What is 0+y^2+z^2=1 ?
The solution to 0+y^2+z^2=1 is Circle with (a,b)=(0,0),r=1