What is (x+1)^2+(y-1)^2=36 ?

The solution to (x+1)^2+(y-1)^2=36 is Circle with (a,b)=(-1,1),r=6

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(x+1)^2+(y-1)^2=36

(x + 1)^{2} + (y - 1)^{2} = 36

(a, b) = (- 1, 1), r = 6

Solution steps

(x + 1)^{2} + (y - 1)^{2} = 36

Rewrite

(x + 1)^{2} + (y - 1)^{2} = 36

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = 6

x^{2} + y^{2} + 6 x + 10 y + 9 = 0

x^{2} + y^{2} - \frac{2}{3} x + \frac{8}{3} y = \frac{19}{9}

x^{2} + 14 x + y^{2} - 2 y - 50 = 0

(x - 2)^{2} + (y - 1.5)^{2} = 9

x^{2} + y^{2} + 2 x + 4 y - 31 = 0

What is (x+1)^2+(y-1)^2=36 ?
The solution to (x+1)^2+(y-1)^2=36 is Circle with (a,b)=(-1,1),r=6