What is x^2-2x+y^2-6y+6=0 ?

The solution to x^2-2x+y^2-6y+6=0 is Circle with (a,b)=(1,3),r=2

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x^2-2x+y^2-6y+6=0

x^{2} - 2 x + y^{2} - 6 y + 6 = 0

(a, b) = (1, 3), r = 2

Solution steps

x^{2} - 2 x + y^{2} - 6 y + 6 = 0

Rewrite

x^{2} - 2 x + y^{2} - 6 y + 6 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (1, 3), r = 2

(x - 2)^{2} + (y - (- 4))^{2} = 1. 7^{2}

x^{2} + y^{2} + y - 11 = 0

x^{2} - 154 x + y^{2} - 160 y = 0

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{16} = 10

(x - 4)^{(2)} + (y - 5)^{(2)} = 49

What is x^2-2x+y^2-6y+6=0 ?
The solution to x^2-2x+y^2-6y+6=0 is Circle with (a,b)=(1,3),r=2