What is x^2+y^2+4x-6y-2=0 ?

The solution to x^2+y^2+4x-6y-2=0 is Circle with (a,b)=(-2,3),r=sqrt(15)

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x^2+y^2+4x-6y-2=0

x^{2} + y^{2} + 4 x - 6 y - 2 = 0

(a, b) = (- 2, 3), r = 15

Solution steps

x^{2} + y^{2} + 4 x - 6 y - 2 = 0

Rewrite

x^{2} + y^{2} + 4 x - 6 y - 2 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 3)^{2} = (15)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 3), r = 15

x^{2} + y^{2} + 8 x - 6 y - 24 = 0

32 = (x - 3)^{2} + (y + 1)^{2}

x^{2} - 10 x + y^{2} + 6 y - 30 = 0

x^{2} - 2 x + 1 + y^{2} + y + \frac{1}{11} = \frac{11}{4}

(- \frac{2}{5} - x)^{2} + (- \frac{6}{5} - y)^{2} = 10

What is x^2+y^2+4x-6y-2=0 ?
The solution to x^2+y^2+4x-6y-2=0 is Circle with (a,b)=(-2,3),r=sqrt(15)