What is the radius x^2+y^2-16x+12y+64=0 ?

The radius x^2+y^2-16x+12y+64=0 is r=6

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radius x^2+y^2-16x+12y+64=0

radius

x^{2} + y^{2} - 16 x + 12 y + 64 = 0

r = 6

Solution steps

x^{2} + y^{2} - 16 x + 12 y + 64 = 0

Rewrite

x^{2} + y^{2} - 16 x + 12 y + 64 = 0

in the form of the standard circle equation

(x - 8)^{2} + (y - (- 6))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (8, - 6), r = 6

And the radius is:

r = 6

x^{2} + y^{2} + 8 x - 6 y - 15 = 0

x^{2} + y^{2} - 8 x + 10 y + 8 = 0

x^{2} + y^{2} + 2 x - 6 y - 6 = 0

(x + 6)^{2} + (y + 5)^{2} = 8

(x - 4)^{2} + (y + 5)^{2} = 49

What is the radius x^2+y^2-16x+12y+64=0 ?
The radius x^2+y^2-16x+12y+64=0 is r=6