What is the radius (x+2)^2+(y-5)^2=16 ?

The radius (x+2)^2+(y-5)^2=16 is r=4

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radius (x+2)^2+(y-5)^2=16

radius

(x + 2)^{2} + (y - 5)^{2} = 16

r = 4

Solution steps

(x + 2)^{2} + (y - 5)^{2} = 16

Rewrite

(x + 2)^{2} + (y - 5)^{2} = 16

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 5)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 2, 5), r = 4

And the radius is:

r = 4

(x - 2)^{2} + (y + 4)^{2} = 9

(x - 2)^{2} + (y + 4)^{2} = 4

(x + 1)^{2} + (y - 1)^{2} = 40

x^{2} + y^{2} - 2 x - 8 y - 19 = 0 (1.5)

x^{2} + y^{2} + 10 x + 8 y - 4 = 0