What is the radius (x+2)^2+(y-6)^2=169 ?

The radius (x+2)^2+(y-6)^2=169 is r=13

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radius (x+2)^2+(y-6)^2=169

radius

(x + 2)^{2} + (y - 6)^{2} = 169

r = 13

Solution steps

(x + 2)^{2} + (y - 6)^{2} = 169

Rewrite

(x + 2)^{2} + (y - 6)^{2} = 169

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 6)^{2} = 1 3^{2}

Therefore the circle properties are:

(a, b) = (- 2, 6), r = 13

And the radius is:

r = 13

x^{2} + y^{2} - 2 x - 8 y - 19 = 0 (1.5) 6

x^{2} + y^{2} - 10 x + 12 y = 195

4 (x - 5)^{2} + 4 y^{2} = 4

x^{2} + 2 x + y^{2} - 2 y = - 1

(x - 9)^{2} + (y - 4)^{2} = 25