What is the radius (x-3)^2=8-(y+3)^2 ?

The radius (x-3)^2=8-(y+3)^2 is r=sqrt(8)

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radius (x-3)^2=8-(y+3)^2

radius

(x - 3)^{2} = 8 - (y + 3)^{2}

r = 8

Solution steps

(x - 3)^{2} = 8 - (y + 3)^{2}

Rewrite

(x - 3)^{2} = 8 - (y + 3)^{2}

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 3))^{2} = (8)^{2}

Therefore the circle properties are:

(a, b) = (3, - 3), r = 8

And the radius is:

r = 8

x^{2} + y^{2} + 10 y + 15 = 0

6 x^{2} + 6 y^{2} + 12 x - y = 0

x^{2} + y^{2} + 10 x - 16 y = - 80

(x + 2)^{2} + (y - 1)^{2} = 16

(x - 3)^{2} + (y - 1)^{2} = 4

What is the radius (x-3)^2=8-(y+3)^2 ?
The radius (x-3)^2=8-(y+3)^2 is r=sqrt(8)