What is the radius 4x^2+4y^2-12x+4y-26=0 ?

The radius 4x^2+4y^2-12x+4y-26=0 is r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius 4x^2+4y^2-12x+4y-26=0

radius

4 x^{2} + 4 y^{2} - 12 x + 4 y - 26 = 0

r = 3

Solution steps

4 x^{2} + 4 y^{2} - 12 x + 4 y - 26 = 0

Rewrite

4 x^{2} + 4 y^{2} - 12 x + 4 y - 26 = 0

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - (- \frac{1}{2}))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, - \frac{1}{2}), r = 3

And the radius is:

r = 3

4 x^{2} + 4 y^{2} + 8 x - y = 0

(x - 2)^{2} + (y - 3)^{2} = 64

x^{2} + (y + 2)^{2} = (20^{2})

x^{2} + y^{2} - 10 x - 8 y + 32 = 0

x^{2} + y^{2} + 6 x + 8 y + 19 = 0

What is the radius 4x^2+4y^2-12x+4y-26=0 ?
The radius 4x^2+4y^2-12x+4y-26=0 is r=3