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Popular >

radius+x^2+y^2-4x=0

Solution

radius

+ x^{2} + y^{2} - 4 x = 0

Solution

r = 2

Solution steps

x^{2} + y^{2} - 4 x = 0

Rewrite

+ x^{2} + y^{2} - 4 x = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 2

And the radius is:

r = 2

Popular Examples

radius x^2-6x+14y-567+y^2=0 radius

x^{2} - 6 x + 14 y - 567 + y^{2} = 0

radius x^2+y^2+2x-4y-4=0 radius

x^{2} + y^{2} + 2 x - 4 y - 4 = 0

radius 6(x-3)^2+6(y+7)^2=216 radius

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

radius x^2+y^2-4x+9x=16 radius

x^{2} + y^{2} - 4 x + 9 x = 16

radius (x+2)^2+(y-3)^2=(-6)^2 radius

(x + 2)^{2} + (y - 3)^{2} = (- 6)^{2}

Frequently Asked Questions (FAQ)

What is the radius+x^2+y^2-4x=0 ?
The radius+x^2+y^2-4x=0 is r=2