What is the circumference x^2+y^2-10x-10y+25=0 ?

The circumference x^2+y^2-10x-10y+25=0 is C=10pi

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circumference x^2+y^2-10x-10y+25=0

circumference

x^{2} + y^{2} - 10 x - 10 y + 25 = 0

C = 10 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 10 x - 10 y + 25 = 0 : r = 5

C = 2 π 5

Refine

C = 10 π

x^{2} + y^{2} + 4 x - 2 y = - 1

4 x^{2} + 4 y^{2} - 4 x + 2 y - 1 = 0

(x - 1)^{2} + (y - 2)^{2} = 4

(x + 2)^{2} + (y - 3)^{2} = 16

x^{2} + y^{2} \leq + 16

What is the circumference x^2+y^2-10x-10y+25=0 ?
The circumference x^2+y^2-10x-10y+25=0 is C=10pi