What is the circumference x^2+y^2+6x-2y-15=0 ?

The circumference x^2+y^2+6x-2y-15=0 is C=10pi

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circumference x^2+y^2+6x-2y-15=0

circumference

x^{2} + y^{2} + 6 x - 2 y - 15 = 0

C = 10 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 6 x - 2 y - 15 = 0 : r = 5

C = 2 π 5

Refine

C = 10 π

(x - 4)^{2} + (y - (- 4))^{2} = 16

x^{2} + y^{2} - 4 = 0

x^{2} + y^{2} + 8 x - 2 y + 15 = 0

3 x^{2} + 3 y^{2} - 12 x + 6 y - 12 = 0

x^{2} - 4 x + y^{2} + 8 y - 5 = 0

What is the circumference x^2+y^2+6x-2y-15=0 ?
The circumference x^2+y^2+6x-2y-15=0 is C=10pi