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Popular >

circumference x^2+y^2-4x-12=0

Solution

circumference

x^{2} + y^{2} - 4 x - 12 = 0

Solution

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 4 x - 12 = 0 : r = 4

C = 2 π 4

Refine

C = 8 π

Popular Examples

circumference 4x^2+4y^2+28x-28y-24=0 circumference

4 x^{2} + 4 y^{2} + 28 x - 28 y - 24 = 0

circumference x^2+14x+y^2-6y-23=0 circumference

x^{2} + 14 x + y^{2} - 6 y - 23 = 0

circumference x^2+y^2=8 circumference

x^{2} + y^{2} = 8

circumference 9x^2+9y^2+18x-18y+14=0 circumference

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

circumference (x-3)^2+(y-2)^2=9 circumference

(x - 3)^{2} + (y - 2)^{2} = 9

Frequently Asked Questions (FAQ)

What is the circumference x^2+y^2-4x-12=0 ?
The circumference x^2+y^2-4x-12=0 is C=8pi