What is the circumference x^2+8x-6y+y^2-11=0 ?

The circumference x^2+8x-6y+y^2-11=0 is C=12pi

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circumference x^2+8x-6y+y^2-11=0

circumference

x^{2} + 8 x - 6 y + y^{2} - 11 = 0

C = 12 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + 8 x - 6 y + y^{2} - 11 = 0 : r = 6

C = 2 π 6

Refine

C = 12 π

(x - (- 1))^{2} + (y - 2)^{2} = 6^{2}

(x - 1)^{2} + (y - 6)^{2} = 25

x^{2} + y^{2} + 8 x - 2 y - 19 = 0

(x - 2)^{2} + (y - 5)^{2} = 16

x^{2} + y^{2} - 18 x - 6 y - 10 = 0

What is the circumference x^2+8x-6y+y^2-11=0 ?
The circumference x^2+8x-6y+y^2-11=0 is C=12pi