What is the circumference (x+1)^2+(y+2)^2=16 ?

The circumference (x+1)^2+(y+2)^2=16 is C=8pi

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circumference (x+1)^2+(y+2)^2=16

circumference

(x + 1)^{2} + (y + 2)^{2} = 16

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 1)^{2} + (y + 2)^{2} = 16 : r = 4

C = 2 π 4

Refine

C = 8 π

x^{2} + y^{2} + 4 x - 8 y = 0

2 x^{2} + 2 y^{2} - 8 x - 12 y + 8 = 0

(x - 3)^{2} + (y + 4)^{2} = 8

x^{2} + y^{2} - 6 y = 16

2 x^{2} + 2 y^{2} + 10 x - 6 y + 3 = 0

What is the circumference (x+1)^2+(y+2)^2=16 ?
The circumference (x+1)^2+(y+2)^2=16 is C=8pi