What is the circumference x^2+y^2+4x-10y+13=0 ?

The circumference x^2+y^2+4x-10y+13=0 is C=8pi

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circumference x^2+y^2+4x-10y+13=0

circumference

x^{2} + y^{2} + 4 x - 10 y + 13 = 0

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 4 x - 10 y + 13 = 0 : r = 4

C = 2 π 4

Refine

C = 8 π

4 x^{2} + 16 x + 15 + 4 y^{2} + 6 y = 0

x^{2} + y^{2} - 10 x - 6 y + 9 = 0

(x - 1)^{2} + (y - 2)^{2} = 3^{2}

(x - 5)^{2} + (y - 9)^{2} = 4

(x - 3)^{2} + (y - 3)^{2} = 7

What is the circumference x^2+y^2+4x-10y+13=0 ?
The circumference x^2+y^2+4x-10y+13=0 is C=8pi