What is the circumference (x-0.5)^2+(y-3.5)^2=4 ?

The circumference (x-0.5)^2+(y-3.5)^2=4 is C=4pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference (x-0.5)^2+(y-3.5)^2=4

circumference

(x - 0.5)^{2} + (y - 3.5)^{2} = 4

C = 4 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 0.5)^{2} + (y - 3.5)^{2} = 4 : r = 2

C = 2 π 2

Refine

C = 4 π

x^{2} + y^{2} - 2 x = 0

(x - 1)^{2} + (y - 1)^{2} = 18

x^{2} + y^{2} + 4 x - 10 y + 11 = 0

(x - 1)^{2} + (y - 3)^{2} = 16

(x + 7)^{2} + (y - 2)^{2} = 81

What is the circumference (x-0.5)^2+(y-3.5)^2=4 ?
The circumference (x-0.5)^2+(y-3.5)^2=4 is C=4pi