What is the circumference (x-1)^2+(y-3)^2=16 ?

The circumference (x-1)^2+(y-3)^2=16 is C=8pi

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circumference (x-1)^2+(y-3)^2=16

circumference

(x - 1)^{2} + (y - 3)^{2} = 16

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 1)^{2} + (y - 3)^{2} = 16 : r = 4

C = 2 π 4

Refine

C = 8 π

(x + 7)^{2} + (y - 2)^{2} = 81

\frac{( x + 6 ) ^{2} + ( y - 7 ) ^{2}}{17} = 1

(x - 1)^{2} + (y - 3)^{2} = 25

(x - 4)^{2} + (y + 2)^{2} = 16

x^{2} + y^{2} + 8 x + 4 y - 3 = 40

What is the circumference (x-1)^2+(y-3)^2=16 ?
The circumference (x-1)^2+(y-3)^2=16 is C=8pi