What is the circumference ((x+6)^2+(y-7)^2)/(17)=1 ?

The circumference ((x+6)^2+(y-7)^2)/(17)=1 is C=2sqrt(17)pi

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circumference ((x+6)^2+(y-7)^2)/(17)=1

circumference

\frac{( x + 6 ) ^{2} + ( y - 7 ) ^{2}}{17} = 1

C = 217 π

Solution steps

C = 2 π r

Find the radius

Radius given

\frac{( x + 6 ) ^{2} + ( y - 7 ) ^{2}}{17} = 1 : r = 17

C = 217 π

(x - 1)^{2} + (y - 3)^{2} = 25

(x - 4)^{2} + (y + 2)^{2} = 16

x^{2} + y^{2} + 8 x + 4 y - 3 = 40

x^{2} + y^{2} \leq 9

4 x - x^{2} - y^{2} - 6 y - 2 = 0

What is the circumference ((x+6)^2+(y-7)^2)/(17)=1 ?
The circumference ((x+6)^2+(y-7)^2)/(17)=1 is C=2sqrt(17)pi