What is the circumference (x-4)^2+(y+2)^2=16 ?

The circumference (x-4)^2+(y+2)^2=16 is C=8pi

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circumference (x-4)^2+(y+2)^2=16

circumference

(x - 4)^{2} + (y + 2)^{2} = 16

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 4)^{2} + (y + 2)^{2} = 16 : r = 4

C = 2 π 4

Refine

C = 8 π

x^{2} + y^{2} + 8 x + 4 y - 3 = 40

x^{2} + y^{2} \leq 9

4 x - x^{2} - y^{2} - 6 y - 2 = 0

x^{2} + y^{2} + 3 x + 2 y - 5 = 0

(x - 6)^{2} + (y - 4)^{2} = 5^{2}

What is the circumference (x-4)^2+(y+2)^2=16 ?
The circumference (x-4)^2+(y+2)^2=16 is C=8pi