What is the circumference x^2+y^2+4x+12y+3=0 ?

The circumference x^2+y^2+4x+12y+3=0 is C=2sqrt(37)pi

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circumference x^2+y^2+4x+12y+3=0

circumference

x^{2} + y^{2} + 4 x + 12 y + 3 = 0

C = 237 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 4 x + 12 y + 3 = 0 : r = 37

C = 237 π

9 x^{2} + 9 y^{2} - 6 x - 2 y - 11 = 0

x^{2} + y^{2} - 6 x - 8 y - 3 = 0

4 x^{2} + 4 y^{2} - 4 x + 8 y - 11 = 0

x^{2} + y^{2} + 5 x + 20 y + 10 = 0

x^{2} + y^{2} + 2 x + 6 y - 104 = 0

What is the circumference x^2+y^2+4x+12y+3=0 ?
The circumference x^2+y^2+4x+12y+3=0 is C=2sqrt(37)pi