What is the circumference (x+1)^2+(y-3)^2=16 ?

The circumference (x+1)^2+(y-3)^2=16 is C=8pi

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circumference (x+1)^2+(y-3)^2=16

circumference

(x + 1)^{2} + (y - 3)^{2} = 16

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 1)^{2} + (y - 3)^{2} = 16 : r = 4

C = 2 π 4

Refine

C = 8 π

(x + 1)^{2} + (y + 1)^{2} = 13

x^{2} + y^{2} = 7 + x

x^{2} + y^{2} - 4 x - 5 = 0

x^{2} - 3 x + y^{2} + 1 = 0

(x - 2)^{2} + y^{2} = 6

What is the circumference (x+1)^2+(y-3)^2=16 ?
The circumference (x+1)^2+(y-3)^2=16 is C=8pi