What is the circumference 4x^2+4y^2+20x-8y+9=0 ?

The circumference 4x^2+4y^2+20x-8y+9=0 is C=2sqrt(5)pi

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circumference 4x^2+4y^2+20x-8y+9=0

circumference

4 x^{2} + 4 y^{2} + 20 x - 8 y + 9 = 0

C = 25 π

Solution steps

C = 2 π r

Find the radius

Radius given

4 x^{2} + 4 y^{2} + 20 x - 8 y + 9 = 0 : r = 5

C = 25 π

x^{2} + y^{2} \leq 4^{2}

(x - 4)^{2} + y^{2} = 8

x^{2} = - y^{2} + 4

x^{2} + (y - 6)^{2} = 9

(x - 1)^{2} + (y - 3)^{2} = 2^{2}

What is the circumference 4x^2+4y^2+20x-8y+9=0 ?
The circumference 4x^2+4y^2+20x-8y+9=0 is C=2sqrt(5)pi