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Popular >

area x^2+y^2<=+16

Solution

area

x^{2} + y^{2} \leq + 16

Solution

A = 16 π

Solution steps

A = π r^{2}

Find the radius

Radius given

x^{2} + y^{2} \leq + 16 : r = 4

A = π 4^{2}

Refine

A = 16 π

Popular Examples

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x^{2} + y^{2} + 6 x - 2 y - 15 = 0

area 100x^2+100y^2-100x+400y+409=0 area

100 x^{2} + 100 y^{2} - 100 x + 400 y + 409 = 0

area x^2+y^2=25 area

x^{2} + y^{2} = 25

Frequently Asked Questions (FAQ)

What is the area x^2+y^2<=+16 ?
The area x^2+y^2<=+16 is A=16pi