What is x^2+4y^2-16=0 ?

The solution to x^2+4y^2-16=0 is Ellipse with (h,k)=(0,0),a=4,b=2

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x^2+4y^2-16=0

x^{2} + 4 y^{2} - 16 = 0

(h, k) = (0, 0), a = 4, b = 2

Solution steps

x^{2} + 4 y^{2} - 16 = 0

Rewrite

x^{2} + 4 y^{2} - 16 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 2

25 x^{2} - 200 x + y^{2} + 4 y + 379 = 0

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 4

\frac{( x - 6 ) ^{2}}{16} + \frac{( y + 3 ) ^{2}}{25} = 1

\frac{x ^{2}}{49} + \frac{y ^{2}}{36} = 1

9 x^{2} + 4 y^{2} + 18 x - 8 y - 131 = 0

What is x^2+4y^2-16=0 ?
The solution to x^2+4y^2-16=0 is Ellipse with (h,k)=(0,0),a=4,b=2