What is (y+9)^2+2(x-4)=0 ?

The solution to (y+9)^2+2(x-4)=0 is Parabola with (h,k)=(4,-9),p=-1/2

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(y+9)^2+2(x-4)=0

(y + 9)^{2} + 2 (x - 4) = 0

(h, k) = (4, - 9), p = - \frac{1}{2}

Solution steps

(y + 9)^{2} + 2 (x - 4) = 0

Rewrite

(y + 9)^{2} + 2 (x - 4) = 0

in the standard form:

4 (- \frac{1}{2}) (x - 4) = (y - (- 9))^{2}

Therefore parabola properties are:

(h, k) = (4, - 9), p = - \frac{1}{2}

(x + 9)^{2} - 2 (y - 4) = 0

x + y^{2} = 25

y^{2} = x - 7

(y - 2)^{2} = 12 (x - 1)

4 x^{2} + 9 y = 36

What is (y+9)^2+2(x-4)=0 ?
The solution to (y+9)^2+2(x-4)=0 is Parabola with (h,k)=(4,-9),p=-1/2