What is (x^2}{12}+\frac{y^2)/9 =1 ?

The solution to (x^2}{12}+\frac{y^2)/9 =1 is Ellipse with (h,k)=(0,0),a=2sqrt(3),b=3

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(x^2}{12}+\frac{y^2)/9 =1

\frac{x ^{2}}{12} + \frac{y ^{2}}{9} = 1

(h, k) = (0, 0), a = 23, b = 3

Solution steps

\frac{x ^{2}}{12} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{12} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 3 ) ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 23, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 23, b = 3

5 x^{2} + 6 y^{2} - 30 x - 24 y + 39 = 0

3 x^{(2)} + 7 y^{(2)} - 12 x - 28 y + 19 = 0

0 = x^{2} + y^{2} + 6 y

\frac{X ^{2}}{25} + \frac{Y ^{2}}{9} = 1

\frac{x ^{2}}{20} + \frac{y ^{2}}{36} = 1

What is (x^2}{12}+\frac{y^2)/9 =1 ?
The solution to (x^2}{12}+\frac{y^2)/9 =1 is Ellipse with (h,k)=(0,0),a=2sqrt(3),b=3