What is (x^2)/8+(y^2)/2 =1 ?

The solution to (x^2)/8+(y^2)/2 =1 is Ellipse with (h,k)=(0,0),a=2sqrt(2),b=sqrt(2)

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(x^2)/8+(y^2)/2 =1

\frac{x ^{2}}{8} + \frac{y ^{2}}{2} = 1

(h, k) = (0, 0), a = 22, b = 2

Solution steps

\frac{x ^{2}}{8} + \frac{y ^{2}}{2} = 1

Rewrite

\frac{x ^{2}}{8} + \frac{y ^{2}}{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 22, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 22, b = 2

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{36} = 1

x^{2} + 4 y^{2} - 64 = 0

\frac{x ^{2}}{5} + \frac{y ^{2}}{8} = 1

\frac{x ^{2}}{140} + \frac{( y - 6 ) ^{2}}{4} = 1

\frac{( x + 3 ) ^{2}}{3} + \frac{( y - 2 ) ^{2}}{4} = 1

What is (x^2)/8+(y^2)/2 =1 ?
The solution to (x^2)/8+(y^2)/2 =1 is Ellipse with (h,k)=(0,0),a=2sqrt(2),b=sqrt(2)