What is (x^2)/5+(y^2)/8 =1 ?

The solution to (x^2)/5+(y^2)/8 =1 is Ellipse with (h,k)=(0,0),a=sqrt(5),b=2sqrt(2)

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(x^2)/5+(y^2)/8 =1

\frac{x ^{2}}{5} + \frac{y ^{2}}{8} = 1

(h, k) = (0, 0), a = 5, b = 22

Solution steps

\frac{x ^{2}}{5} + \frac{y ^{2}}{8} = 1

Rewrite

\frac{x ^{2}}{5} + \frac{y ^{2}}{8} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 5 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 22

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 22, a = 5

\frac{x ^{2}}{140} + \frac{( y - 6 ) ^{2}}{4} = 1

\frac{( x + 3 ) ^{2}}{3} + \frac{( y - 2 ) ^{2}}{4} = 1

9 x^{2} - 54 x + 4 y^{2} = - 45

x^{2} + 3 y^{2} + x - 2 y - 1 = 0

(\frac{x + 7}{16})^{2} + \frac{( y + 5 ) ^{2}}{16} = 1

What is (x^2)/5+(y^2)/8 =1 ?
The solution to (x^2)/5+(y^2)/8 =1 is Ellipse with (h,k)=(0,0),a=sqrt(5),b=2sqrt(2)