y^2-4y-8x-12=0

解答

y^{2} - 4 y - 8 x - 12 = 0

(h, k) = (- 2, 2), p = 2

求解步骤

y^{2} - 4 y - 8 x - 12 = 0

将

y^{2} - 4 y - 8 x - 12 = 0

改写为标准形式

4 \cdot 2 (x - (- 2)) = (y - 2)^{2}

因此抛物线性质是:

(h, k) = (- 2, 2), p = 2

f (x) = x^{2} - 5 x

3 x^{2} + 2 y = 26

y^{2} = - 2 x

x^{2} + y^{2} - 4 x + 10 y + 13 = 0

x^{2} + y^{2} + 2 x + 6 y + 2 = 0