What is y^2-4y-8x-12=0 ?

The solution to y^2-4y-8x-12=0 is Parabola with (h,k)=(-2,2),p=2

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y^2-4y-8x-12=0

y^{2} - 4 y - 8 x - 12 = 0

(h, k) = (- 2, 2), p = 2

Solution steps

y^{2} - 4 y - 8 x - 12 = 0

Rewrite

y^{2} - 4 y - 8 x - 12 = 0

in the standard form

4 \cdot 2 (x - (- 2)) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (- 2, 2), p = 2

f (x) = x^{2} - 5 x

3 x^{2} + 2 y = 26

y^{2} = - 2 x

x^{2} + y^{2} - 4 x + 10 y + 13 = 0

x^{2} + y^{2} + 2 x + 6 y + 2 = 0

What is y^2-4y-8x-12=0 ?
The solution to y^2-4y-8x-12=0 is Parabola with (h,k)=(-2,2),p=2