What is ((x+4)^2)/(49)+((y-4)^2)/(25)=1 ?

The solution to ((x+4)^2)/(49)+((y-4)^2)/(25)=1 is Ellipse with (h,k)=(-4,4),a=7,b=5

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((x+4)^2)/(49)+((y-4)^2)/(25)=1

\frac{( x + 4 ) ^{2}}{49} + \frac{( y - 4 ) ^{2}}{25} = 1

(h, k) = (- 4, 4), a = 7, b = 5

Solution steps

\frac{( x + 4 ) ^{2}}{49} + \frac{( y - 4 ) ^{2}}{25} = 1

Rewrite

\frac{( x + 4 ) ^{2}}{49} + \frac{( y - 4 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 4 ) ) ^{2}}{7 ^{2}} + \frac{( y - 4 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 4, 4), a = 7, b = 5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 4, 4), a = 7, b = 5

y^{2} + \frac{x ^{2}}{4} = 1

f, f = 3 - x f (x)^{- 1} (x)

\frac{( x + 3 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{25} - 1 = 0

\frac{( x - 4 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{9} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{4 - 16} = 1

What is ((x+4)^2)/(49)+((y-4)^2)/(25)=1 ?
The solution to ((x+4)^2)/(49)+((y-4)^2)/(25)=1 is Ellipse with (h,k)=(-4,4),a=7,b=5