What is ((x+7)^2)/(16)+((y-4)^2)/(25)=1 ?

The solution to ((x+7)^2)/(16)+((y-4)^2)/(25)=1 is Ellipse with (h,k)=(-7,4),a=4,b=5

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((x+7)^2)/(16)+((y-4)^2)/(25)=1

\frac{( x + 7 ) ^{2}}{16} + \frac{( y - 4 ) ^{2}}{25} = 1

(h, k) = (- 7, 4), a = 4, b = 5

Solution steps

\frac{( x + 7 ) ^{2}}{16} + \frac{( y - 4 ) ^{2}}{25} = 1

Rewrite

\frac{( x + 7 ) ^{2}}{16} + \frac{( y - 4 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 7 ) ) ^{2}}{4 ^{2}} + \frac{( y - 4 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 7, 4), a = 4, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 7, 4), b = 5, a = 4

49 x^{2} + y^{2} - 14 y = 0

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 4

x^{2} + 5 y^{2} = 2021 y

(x + y) - x^{2} = x^{2} + y^{2}

64 x^{2} + 81 y^{2} = 81

What is ((x+7)^2)/(16)+((y-4)^2)/(25)=1 ?
The solution to ((x+7)^2)/(16)+((y-4)^2)/(25)=1 is Ellipse with (h,k)=(-7,4),a=4,b=5