What is 1=(x/(84.5))^2+(y/(33.5))^2 ?

The solution to 1=(x/(84.5))^2+(y/(33.5))^2 is Ellipse with (h,k)=(0,0),a=84.5,b=33.5

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1=(x/(84.5))^2+(y/(33.5))^2

1 = (\frac{x}{84.5})^{2} + (\frac{y}{33.5})^{2}

(h, k) = (0, 0), a = 84.5, b = 33.5

Solution steps

1 = (\frac{x}{84.5})^{2} + (\frac{y}{33.5})^{2}

Rewrite

1 - (\frac{x}{84.5})^{2} - (\frac{y}{33.5})^{2} = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{84. 5 ^{2}} + \frac{( y - 0 ) ^{2}}{33. 5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 84.5, b = 33.5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 84.5, b = 33.5

2 x^{2} + 3 y^{2} = 6

4 x^{2} + 5 y^{2} + 16 x - 20 y + 16 = 0

x^{2} + (\frac{y}{4})^{2} = 1

\frac{( x - 2 ) ^{2}}{4} + \frac{( y - 1 ) ^{2}}{3} = 1

2 x^{2} + y^{2} = 16

What is 1=(x/(84.5))^2+(y/(33.5))^2 ?
The solution to 1=(x/(84.5))^2+(y/(33.5))^2 is Ellipse with (h,k)=(0,0),a=84.5,b=33.5