What is 2x^2+y^2=16 ?

The solution to 2x^2+y^2=16 is Ellipse with (h,k)=(0,0),a=2sqrt(2),b=4

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2x^2+y^2=16

2 x^{2} + y^{2} = 16

(h, k) = (0, 0), a = 22, b = 4

Solution steps

2 x^{2} + y^{2} = 16

Rewrite

2 x^{2} + y^{2} = 16

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 22, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 22

4 (x - 4)^{2} + 9 (y - 2)^{2} = 36

\frac{( y + 7 ) ^{2}}{16} + \frac{( x - 5 ) ^{2}}{25} = 1

\frac{4}{x + y i} = x - y i

4 (x + 3)^{2} + y^{2} = 16

2 (1 + 2 y) (y - 2) = - (2 x - 3) (x - 7)

What is 2x^2+y^2=16 ?
The solution to 2x^2+y^2=16 is Ellipse with (h,k)=(0,0),a=2sqrt(2),b=4