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vertices 3y^2=24x

Solution

vertices

3 y^{2} = 24 x

Solution

(h, k) = (0, 0), p = 2

Solution steps

3 y^{2} = 24 x

Rewrite

3 y^{2} = 24 x

in the standard form:

4 \cdot 2 (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 2

Popular Examples

vertices f(x)=x^2-6x vertices

f (x) = x^{2} - 6 x

directrix y^2+12x+4y-32=0 directrix

y^{2} + 12 x + 4 y - 32 = 0

radius x^2+y^2-18x-14y+124=0 radius

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

vertices (x^2)/9+(y^2)/(25)=1 vertices

\frac{x ^{2}}{9} + \frac{y ^{2}}{25} = 1

9(x-1)^2-16(y+2)^2=144

9 (x - 1)^{2} - 16 (y + 2)^{2} = 144

Frequently Asked Questions (FAQ)

What is the vertices 3y^2=24x ?
The vertices 3y^2=24x is (h,k)=(0,0),p=2