What is 1-(x^2}{16}-\frac{y^2)/9 =0 ?

The solution to 1-(x^2}{16}-\frac{y^2)/9 =0 is Ellipse with (h,k)=(0,0),a=4,b=3

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1-(x^2}{16}-\frac{y^2)/9 =0

1 - \frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 0

(h, k) = (0, 0), a = 4, b = 3

Solution steps

1 - \frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 0

Rewrite

1 - \frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 3

4 x^{2} + y^{2} + 16 x + 16 y - 64 = 0

5 x^{2} + 9 y^{2} - 10 x - 36 y = 4

(\frac{x ^{2}}{16}) + (\frac{y ^{2}}{4}) = 1

\frac{( x + 2 ) ^{2}}{15} + \frac{y ^{2}}{64} = 1

(x^{2} + 8 x) + (3 y^{2} + 8 y) = 11

What is 1-(x^2}{16}-\frac{y^2)/9 =0 ?
The solution to 1-(x^2}{16}-\frac{y^2)/9 =0 is Ellipse with (h,k)=(0,0),a=4,b=3