What is ((x+2)^2)/9+(y^2)/(16)=1 ?

The solution to ((x+2)^2)/9+(y^2)/(16)=1 is Ellipse with (h,k)=(-2,0),a=3,b=4

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((x+2)^2)/9+(y^2)/(16)=1

\frac{( x + 2 ) ^{2}}{9} + \frac{y ^{2}}{16} = 1

(h, k) = (- 2, 0), a = 3, b = 4

Solution steps

\frac{( x + 2 ) ^{2}}{9} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{9} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 0), a = 3, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 0), b = 4, a = 3

(\frac{( x - 2 ) ^{2}}{16}) + (\frac{y ^{2}}{9}) = 1

\frac{x}{x ^{2} + y ^{2}} = \frac{3}{2}

4 x^{2} + 25 y^{2} - 50 y - 75 = 0

x^{2} + 4 y^{2} - 2.71 = 0

\frac{( x - 5 ) ^{2}}{144} + \frac{( y + 2 ) ^{2}}{169} = 1

What is ((x+2)^2)/9+(y^2)/(16)=1 ?
The solution to ((x+2)^2)/9+(y^2)/(16)=1 is Ellipse with (h,k)=(-2,0),a=3,b=4