What is the vertices (x^2)/(a^2)+(y^2)/(b^2)=1 ?

The vertices (x^2)/(a^2)+(y^2)/(b^2)=1 is (a,0),(-a,0)

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vertices (x^2)/(a^2)+(y^2)/(b^2)=1

vertices

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

(a, 0), (- a, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1 :

Ellipse with center

(h, k) = (0, 0), a = a, b = b

(0 + a, 0), (0 - a, 0)

Refine

(a, 0), (- a, 0)

5 x^{2} + 2 y^{2} = 50

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1

3 x^{2} + y^{2} = 84

25 x^{2} + y^{2} - 100 x + 8 y + 91 = 0

9 x^{2} + 4 y^{2} + 72 x - 40 y + 208 = 0

What is the vertices (x^2)/(a^2)+(y^2)/(b^2)=1 ?
The vertices (x^2)/(a^2)+(y^2)/(b^2)=1 is (a,0),(-a,0)