What is the vertices 4-9x^2-2y^2=0 ?

The vertices 4-9x^2-2y^2=0 is (0,sqrt(2)),(0,-sqrt(2))

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vertices 4-9x^2-2y^2=0

vertices

4 - 9 x^{2} - 2 y^{2} = 0

(0, 2), (0, - 2)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

4 - 9 x^{2} - 2 y^{2} = 0 :

Ellipse with center

(h, k) = (0, 0), b = 2, a = \frac{2}{3}

(0, 0 + 2), (0, 0 - 2)

Refine

(0, 2), (0, - 2)

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{25} = 1

\frac{( x - 5 ) ^{2}}{9} + \frac{( y - 4 ) ^{2}}{36} = 1

25 x^{2} + 9 y^{2} - 225 = 0

64 x^{2} + y^{2} = 64

\frac{x ^{2}}{36} + \frac{y ^{2}}{100} = 1

What is the vertices 4-9x^2-2y^2=0 ?
The vertices 4-9x^2-2y^2=0 is (0,sqrt(2)),(0,-sqrt(2))