What is the vertices (x^2)/(36)+(y^2)/(100)=1 ?

The vertices (x^2)/(36)+(y^2)/(100)=1 is (0,10),(0,-10)

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vertices (x^2)/(36)+(y^2)/(100)=1

vertices

\frac{x ^{2}}{36} + \frac{y ^{2}}{100} = 1

(0, 10), (0, - 10)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{x ^{2}}{36} + \frac{y ^{2}}{100} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 10, a = 6

(0, 0 + 10), (0, 0 - 10)

Refine

(0, 10), (0, - 10)

6 x^{2} + 6 y^{2} + 24 x + 36 y = 0

64 x^{2} + 9 y^{2} = 576

x^{2} + \frac{y ^{2}}{4} = 1

\frac{x ^{2}}{100} + \frac{y ^{2}}{44} = 1

\frac{x ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

What is the vertices (x^2)/(36)+(y^2)/(100)=1 ?
The vertices (x^2)/(36)+(y^2)/(100)=1 is (0,10),(0,-10)