What is the vertices 25x^2+y^2-4y-21=0 ?

The vertices 25x^2+y^2-4y-21=0 is (0,7),(0,-3)

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vertices 25x^2+y^2-4y-21=0

vertices

25 x^{2} + y^{2} - 4 y - 21 = 0

(0, 7), (0, - 3)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

25 x^{2} + y^{2} - 4 y - 21 = 0 :

Ellipse with center

(h, k) = (0, 2), b = 5, a = 1

(0, 2 + 5), (0, 2 - 5)

Refine

(0, 7), (0, - 3)

9 x^{2} - 72 x + y^{2} + 4 y + 112 = 0

4 x^{2} + 9 y^{2} = 1

4 x^{2} + y^{2} = 4

36 x^{2} + 9 y^{2} + 48 x - 36 y + 43 = 0

16 x^{2} - 96 x + 4 y^{2} = - 80

What is the vertices 25x^2+y^2-4y-21=0 ?
The vertices 25x^2+y^2-4y-21=0 is (0,7),(0,-3)