What is the vertices 9x^2+25y^2+90x=0 ?

The vertices 9x^2+25y^2+90x=0 is (0,0),(-10,0)

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vertices 9x^2+25y^2+90x=0

vertices

9 x^{2} + 25 y^{2} + 90 x = 0

(0, 0), (- 10, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

9 x^{2} + 25 y^{2} + 90 x = 0 :

Ellipse with center

(h, k) = (- 5, 0), a = 5, b = 3

(- 5 + 5, 0), (- 5 - 5, 0)

Refine

(0, 0), (- 10, 0)

2 x^{2} + 3 y^{2} + 4 x - 6 y - 1 = 0

\frac{x ^{2}}{36} + \frac{y ^{2}}{25} = 1

36 x^{2} + 9 y^{2} = 324

\frac{( x - 6 ) ^{2}}{2} + (y - 2)^{2} = 1

4 x^{2} + y^{2} = 4 x

What is the vertices 9x^2+25y^2+90x=0 ?
The vertices 9x^2+25y^2+90x=0 is (0,0),(-10,0)